document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=636723>Question 636723</A>: <I><SPAN STYLE=\"word-break: break-all;\"> divide 184 into two parts such that one-third of one part may exceed one-seventh of the other part by 4<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #401185 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=401185\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> divide 184 into two parts such that one-third of one part may exceed one-seventh of the other part by 4<BR>\n" );
document.write( "ans:-<BR>\n" );
document.write( "let one part is x & the other part is 184-x<BR>\n" );
document.write( "as per question x/3=(184-x)/7+4<BR>\n" );
document.write( "by simplifying 7x=3(184-x)+4*7*3=552-3x+84=636-3x<BR>\n" );
document.write( "or10x=636 =>x=63.6<BR>\n" );
document.write( "& other part=184-63.6=120.4 ans </SPAN>\n" );
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