document.write( "Question 636488: Evaluate.\r
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document.write( "tan(2 arc tan of 5/12)\r
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document.write( "arc cos(sin of 11pi/6)\r
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document.write( "sin(1/2 arc tan of 24/7) \n" );
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Algebra.Com's Answer #401183 by lwsshak3(11628) ![]() You can put this solution on YOUR website! Evaluate. \n" ); document.write( "tan(2 arc tan of 5/12) \n" ); document.write( "identity: tan 2x=(2 tanx)/(1-tan^2x) \n" ); document.write( "tan x=5/12 \n" ); document.write( "tan(2 arc tan of 5/12) \n" ); document.write( "=(2*(5/12))/(1-(5/12)^2) \n" ); document.write( "=(10/12)/1-(25/144) \n" ); document.write( "=(120/144)/)119/144=120/119 \n" ); document.write( ".. \n" ); document.write( "arc cos(sin of 11pi/6) \n" ); document.write( "sin 11pi/6=sin 5π/6=.5 \n" ); document.write( "arc cos(sin of 11pi/6) \n" ); document.write( "arc cos(.5) \n" ); document.write( "=-√3/2 \n" ); document.write( ".. \n" ); document.write( "sin(1/2 arc tan of 24/7) \n" ); document.write( "Identity: sin x/2=±√[(1-cos x)/2] \n" ); document.write( "tan x=24/7=opp side/adj side \n" ); document.write( "hypotenuse=√opp side^2+adj side^2)=√(24^2+7^2)=√576+49=√625=25 \n" ); document.write( "hypotenuse=25 \n" ); document.write( "cos x=adj side/hypotenuse=7/25 \n" ); document.write( "sin(1/2 arc tan of 24/7) \n" ); document.write( "=√[(1-cos x)/2] \n" ); document.write( "=√[(1-7/25)/2] \n" ); document.write( "=√[(18/25)/2] \n" ); document.write( "=√18/50 \n" ); document.write( "=√(9/25) \n" ); document.write( "=3/5 \n" ); document.write( "=0.6 \n" ); document.write( " |