document.write( "Question 636443: Give the vertex, focus, and directrix of the parabola\r
\n" ); document.write( "\n" ); document.write( "16x^2=y
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Algebra.Com's Answer #401149 by lwsshak3(11628)\"\" \"About 
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Give the vertex, focus, and directrix of the parabola
\n" ); document.write( "16x^2=y
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\n" ); document.write( "Form of equation for a parabola that opens upwards: x^2=4py
\n" ); document.write( "For given problem:
\n" ); document.write( "x^2=(1/16)y
\n" ); document.write( "4p=1/16
\n" ); document.write( "p=1/64
\n" ); document.write( "Equation:
\n" ); document.write( "x^2=y/64
\n" ); document.write( "..
\n" ); document.write( "vertex: (0,0)
\n" ); document.write( "axis of symmetry: x=0
\n" ); document.write( "focus: (0, 1/64) (p distance above vertex on the axis of symmetry)
\n" ); document.write( "directrix: y=-1/64 (p distance below vertex on the axis of symmetry)
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