document.write( "Question 636443: Give the vertex, focus, and directrix of the parabola\r
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document.write( "16x^2=y \n" );
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Algebra.Com's Answer #401149 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Give the vertex, focus, and directrix of the parabola \n" ); document.write( "16x^2=y \n" ); document.write( "** \n" ); document.write( "Form of equation for a parabola that opens upwards: x^2=4py \n" ); document.write( "For given problem: \n" ); document.write( "x^2=(1/16)y \n" ); document.write( "4p=1/16 \n" ); document.write( "p=1/64 \n" ); document.write( "Equation: \n" ); document.write( "x^2=y/64 \n" ); document.write( ".. \n" ); document.write( "vertex: (0,0) \n" ); document.write( "axis of symmetry: x=0 \n" ); document.write( "focus: (0, 1/64) (p distance above vertex on the axis of symmetry) \n" ); document.write( "directrix: y=-1/64 (p distance below vertex on the axis of symmetry) \n" ); document.write( " |