document.write( "Question 636615: k + 4 + k^2 -5k + 8
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\n" ); document.write( "k + 1 1 - k k^2 -1 \n" ); document.write( "

Algebra.Com's Answer #401147 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
k 4 k^2 -5k + 8
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\n" ); document.write( "k + 1 1 - k k^2 -1\r
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\n" ); document.write( "Rewrite:
\n" ); document.write( "k 4 k^2 -5k + 8
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\n" ); document.write( "k + 1 k - 1 k^2 -1\r
\n" ); document.write( "\n" ); document.write( "lcm = (k^2-1)
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\n" ); document.write( "Rewrite each fraction with the lcm as its denominator:
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\n" ); document.write( "[k(k-1) -4(k+1) +k^2-5k+8]/[k^2-1]
\n" ); document.write( "------
\n" ); document.write( "[k^2-k-4k-4+k^2-5k+8]/[k^2-1]
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\n" ); document.write( "[2k^2-10k+8]/[k^2-1]
\n" ); document.write( "----
\n" ); document.write( "= [2(k^2-5k+4)]/[k^2-1]
\n" ); document.write( "-----
\n" ); document.write( "= [2(k-4)(k-1)]/[(k+1)(k-1)]
\n" ); document.write( "-----
\n" ); document.write( "= [2(k-4)]/[k+1]
\n" ); document.write( "=====================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "==================== \n" ); document.write( "

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