document.write( "Question 636617: 1 + 1
\n" ); document.write( "--
\n" ); document.write( "a
\n" ); document.write( "-------------------
\n" ); document.write( "1 - 1
\n" ); document.write( "--
\n" ); document.write( "2a
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #401138 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
1 + 1
\n" ); document.write( "--
\n" ); document.write( "a
\n" ); document.write( "-------------------
\n" ); document.write( "1 - 1
\n" ); document.write( "--
\n" ); document.write( "2a \r
\n" ); document.write( "\n" ); document.write( "======================
\n" ); document.write( "= [(1+a)/a]/[(1-2a)/2a]
\n" ); document.write( "-------
\n" ); document.write( "Invert the denominator and multiply:
\n" ); document.write( "-----
\n" ); document.write( "= [(1+a)/a] times [(2a)/(1-2a)]
\n" ); document.write( "------
\n" ); document.write( "Cancel the common \"a\" factor to get:
\n" ); document.write( "-----
\n" ); document.write( "= [(1+a)/1] times [(2)/(1-2a)]
\n" ); document.write( "----
\n" ); document.write( "= (2+2a)/(1-2a)
\n" ); document.write( "====================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "=============
\n" ); document.write( "
\n" ); document.write( "
\n" );