document.write( "Question 636617: 1 + 1
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document.write( "a
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document.write( "1 - 1
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document.write( "2a
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Algebra.Com's Answer #401138 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 1 + 1 \n" ); document.write( "-- \n" ); document.write( "a \n" ); document.write( "------------------- \n" ); document.write( "1 - 1 \n" ); document.write( "-- \n" ); document.write( "2a \r \n" ); document.write( "\n" ); document.write( "====================== \n" ); document.write( "= [(1+a)/a]/[(1-2a)/2a] \n" ); document.write( "------- \n" ); document.write( "Invert the denominator and multiply: \n" ); document.write( "----- \n" ); document.write( "= [(1+a)/a] times [(2a)/(1-2a)] \n" ); document.write( "------ \n" ); document.write( "Cancel the common \"a\" factor to get: \n" ); document.write( "----- \n" ); document.write( "= [(1+a)/1] times [(2)/(1-2a)] \n" ); document.write( "---- \n" ); document.write( "= (2+2a)/(1-2a) \n" ); document.write( "==================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============= \n" ); document.write( " \n" ); document.write( " |