document.write( "Question 636618: The intensity of sound (in Watts per square meter, or \"W\"/\"m\" ^2) varies inversely with the distance from the source. Suppose that a particular sound has in intensity of 90 \"W\"/\"m\" ^2 at a distance of 5 meters. How much farther away would you find the intensity at 40 \"W\"/\"m\" ^2?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "thanks so much for your help on this I really appreciate your time :) \n" ); document.write( "
Algebra.Com's Answer #401134 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The intensity of sound (in Watts per square meter, or \"W\"/\"m\" ^2) varies inversely with the distance from the source. Suppose that a particular sound has in intensity of 90 \"W\"/\"m\" ^2 at a distance of 5 meters. How much farther away would you find the intensity at 40 \"W\"/\"m\" ^2? \r
\n" ); document.write( "\n" ); document.write( "-------
\n" ); document.write( "W =k/d
\n" ); document.write( "---
\n" ); document.write( "Solve for \"k\":
\n" ); document.write( "90 = k/5
\n" ); document.write( "k = 450
\n" ); document.write( "-------
\n" ); document.write( "Equation:
\n" ); document.write( "40 = 450/d
\n" ); document.write( "d = 450/40
\n" ); document.write( "d = 11 1/4 meters
\n" ); document.write( "====================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "=============== \n" ); document.write( "
\n" );