document.write( "Question 58570: Can you help me solve this?
\n" ); document.write( "radical sign x-1 = x-3
\n" ); document.write( "The radical sign is only by x-1
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\n" ); document.write( "CH \n" ); document.write( "
Algebra.Com's Answer #40113 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
Can you help me solve this?\r\n" );
document.write( "radical sign x-1 = x-3\r\n" );
document.write( "The radical sign is only by x-1\r\n" );
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document.write( "√x-1 = x-3\r\n" );
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document.write( "Square both sides\r\n" );
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document.write( "(√x - 1)² = (x - 3)²\r\n" );
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document.write( "When you square a square root, you \r\n" );
document.write( "take away the radical\r\n" );
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document.write( "    x - 1 = (x - 3)²\r\n" );
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document.write( "Now you square the right side by writing\r\n" );
document.write( "(x - 3)² as (x - 3)(x - 3)\r\n" );
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document.write( "    x - 1 = (x - 3)(x - 3)\r\n" );
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document.write( "You finish it! It will become a quadratic \r\n" );
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document.write( "equation.  You will get solutions 2 and 5\r\n" );
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document.write( "However you must ALWAYS check radical equations! \r\n" );
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document.write( "You will find that the 2 does not check in the\r\n" );
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document.write( "original equation, but the 5 does check.\r\n" );
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document.write( "So you discard the 2 solution as an extraneous \r\n" );
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document.write( "solution, and the only correct solution is 5.\r\n" );
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document.write( "Edwin
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