document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=636561>Question 636561</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The base of a triangle is 8 cm less than its height. If the area of the triangle is 42cm^2, find its base and height. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #401096 by </B><A HREF=/tutors/aboutme.mpl?userid=shebi123><B>shebi123(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=shebi123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=401096\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let <BR>\n" );
document.write( "the height = x <BR>\n" );
document.write( "Base = x-8\r<BR>\n" );
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document.write( "Formula<BR>\n" );
document.write( "Area= 1/2(height *base)\r<BR>\n" );
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document.write( "Solution \r<BR>\n" );
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document.write( "1/2{x(x-8)}=42<BR>\n" );
document.write( "x(x-8)=84<BR>\n" );
document.write( "x^2-8x-84=0<BR>\n" );
document.write( "x^2 -14x+6x-84=0<BR>\n" );
document.write( "(x+6)(x-14)=0<BR>\n" );
document.write( "x= -6,14\r<BR>\n" );
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document.write( "We'll take positive one<BR>\n" );
document.write( "Base=x=14cm<BR>\n" );
document.write( "Height =x-8=6cm </SPAN>\n" );
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