document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=636441>Question 636441</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 30 ft and its area is 54 ft^2. Find the dimensions. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #401078 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=401078\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the length of the rectangle be l<BR>\n" );
document.write( "and breadth be b<BR>\n" );
document.write( "ATQ 2(l+b)=30<BR>\n" );
document.write( "so l+b=15...........eq^n 1<BR>\n" );
document.write( "lb=54.............eq^n 2 <BR>\n" );
document.write( "so l-b=sqrt{(l+b)^2-4lb}=sqrt{15^2-4*54}=sqrt(225-216)=sqrt 9=3........eq^n 3<BR>\n" );
document.write( "adding eq^n 1 & 2 <BR>\n" );
document.write( "    2l=18<BR>\n" );
document.write( "    l=18/2=9<BR>\n" );
document.write( "    b=15-9=6  ans<BR>\n" );
document.write( "               </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );