document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=636507>Question 636507</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Billy is twice as old as his son. in 10 years, the ratio of their ages will be 3:5. find their present ages </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #401073 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=401073\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the age of the son be x<BR>\n" );
document.write( "and the age of Billy be 2x<BR>\n" );
document.write( "  after 10 years<BR>\n" );
document.write( " the ratio of their ages will be 3:5<BR>\n" );
document.write( " then (x+10)/(2x+10) =3/5<BR>\n" );
document.write( " or 3(2x+10)=5(x+10)<BR>\n" );
document.write( " or 6x+30=5x+50<BR>\n" );
document.write( " or 6x-5x=50-30<BR>\n" );
document.write( " or x=20 son's age<BR>\n" );
document.write( " So Billy is 2x=2*20=40 years ans<BR>\n" );
document.write( "    </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );