document.write( "Question 636453: Find the center, foci, vertices, and asymptotes. Please show all your steps.\r
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document.write( "y^2/25-x^2=1 \n" );
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Algebra.Com's Answer #401044 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Find the center, foci, vertices, and asymptotes. Please show all your steps. \n" ); document.write( "y^2/25-x^2=1 \n" ); document.write( "** \n" ); document.write( "This is a hyperbola with vertical transverse axis. \n" ); document.write( "Its standard form of equation \n" ); document.write( ".. \n" ); document.write( "For given equation of a hyperbola: \n" ); document.write( "center: (0,0) \n" ); document.write( ".. \n" ); document.write( "a^2=25 \n" ); document.write( "a=√25=5 \n" ); document.write( "vertices: (0, 0±a)=(0, 0±5)=(0,-5) and (0,5) \n" ); document.write( ".. \n" ); document.write( "b^2=1 \n" ); document.write( "b=1 \n" ); document.write( ".. \n" ); document.write( "c^2=a^2+b^2=25+1=26 \n" ); document.write( "c=√26≈5.1 \n" ); document.write( "Foci: (0, 0±c)=(0, 0±5.1)=(0,-5.1) and (0,5.1) \n" ); document.write( ".. \n" ); document.write( "Asymptotes are lines that intersect at center (0,0). Equation: y=mx+b, m=slope, b=y-intercept \n" ); document.write( "slopes of asymptotes of hyperbolas with vertical transverse axis=±a/b=±5/1=±5 \n" ); document.write( "Equation of asymptote with negative slope (-5) \n" ); document.write( "y=-5x+b \n" ); document.write( "y=-5x+0 \n" ); document.write( "y=-5x \n" ); document.write( ".. \n" ); document.write( "Equation of asymptote with positive slope (5) \n" ); document.write( "y=5x+b \n" ); document.write( "y=5x+0 \n" ); document.write( "y=5x \n" ); document.write( " \n" ); document.write( " |