document.write( "Question 636461: How much 20% antifreeze solution must be mixed with a 80% antifreeze solution to produce 30 gallons of a 60% disinfectant solution? \n" ); document.write( "
Algebra.Com's Answer #401035 by Maths68(1474)\"\" \"About 
You can put this solution on YOUR website!
Solution A
\n" ); document.write( "===========
\n" ); document.write( "Amount = x gallons
\n" ); document.write( "Concentration = 20%=0.2\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Solution B
\n" ); document.write( "===========
\n" ); document.write( "Amount = 30-x gallons
\n" ); document.write( "Concentration = 80%=0.8\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Mixture
\n" ); document.write( "=======
\n" ); document.write( "Amount = 30 gallons
\n" ); document.write( "Concentration = 60% = 0.6\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "(Amount of Solution A)(Concentration of Solution A)+(Amount of Solution B)(Concentration of Solution B)=(Amount of Mixture)(Concentration of Mixture)
\n" ); document.write( "(x)(0.2)+(30-x)(0.8)=(30)(0.6)
\n" ); document.write( "0.2x+24-0.8x=18
\n" ); document.write( "0.2x-0.8x=18-24
\n" ); document.write( "-0.6x=-6
\n" ); document.write( "-0.6x/-0.6=-6/-0.6
\n" ); document.write( "x=10\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "10 gallon of 20% antifreeze solution must be mixed with 20 gallons of 80% antifreeze solution to produce 30 gallons of a 60% disinfectant solution.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );