document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=636468>Question 636468</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Train A leaves a station traveling at 32 km/h. Two hours later, train B leaves the same station traveling in the same direction at 52 km/h. How long does it take train B to catch up to train A? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #401031 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=401031\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hint: the equation for train A is y = 32x where x is the time and y is the distance traveled. The equation for train B is y = 52(x-2) where again x is the time and y is the distance traveled\r<BR>\n" );
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document.write( "The two will meet when the two distances are the same. So solve 32x = 52(x-2) for x to find your answer. </SPAN>\n" );
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