document.write( "Question 636429: w(w+2)=a
\n" ); document.write( "(w+2)(w+4)=a+20
\n" ); document.write( "W^2+2w=a
\n" ); document.write( "w^2+6w+8=a+20
\n" ); document.write( "4w+8=20
\n" ); document.write( "4w=12
\n" ); document.write( "w=3 \r
\n" ); document.write( "\n" ); document.write( "Please could someone show me how to check this problem I did ,I have to show a check and I am lost please help
\n" ); document.write( "

Algebra.Com's Answer #401023 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "w(w+2)=a
\n" ); document.write( "(w+2)(w+4)=a+20
\n" ); document.write( "W^2+2w=a
\n" ); document.write( "w^2+6w+8=a+20
\n" ); document.write( "4w+8=20
\n" ); document.write( "4w=12
\n" ); document.write( "w=3 \r
\n" ); document.write( "\n" ); document.write( "Please could someone show me how to check this problem I did ,I have to show a check and I am lost please help\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Your w = 3 solution is correct. Good work!! \r
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\n" ); document.write( "\n" ); document.write( "However, you now need to find the value of a, by substituting 3 for w in any of the equations with the 2 variables, a and w. Having found a and w, you can then substitute each value for each variable into any or all equations with the two variables to determine if those variable-values make those equations true.\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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