document.write( "Question 7240: one side of a triangle is 2 inches more than the shortest side. the third side is twice the length of the shortest side. if the triangle perimeter is 37 inches, find the length of each \n" ); document.write( "
Algebra.Com's Answer #4010 by sabanasir(22)\"\" \"About 
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well since the other two sides are conneccted with shortest then we say the shortest to be 'x'
\n" ); document.write( "now one side which is 2 inches more that of shortest side, it wud b:
\n" ); document.write( " x+2
\n" ); document.write( "and the 3rd side said to be twice shortest one's length then it wud b:
\n" ); document.write( " 2x
\n" ); document.write( " now its said the perimeter. a perimeter is a sum of all the sidees' length, so:
\n" ); document.write( "meaning:
\n" ); document.write( "shortest side+second side+third sided = 37
\n" ); document.write( "(x)+(x+2)+(2x) = 37
\n" ); document.write( "x+ 2x + x = 37 -2
\n" ); document.write( "4x = 35( r u sure it is 37?? if it is then the lenthgs are to be in decimals)
\n" ); document.write( "x=35/4
\n" ); document.write( "x=8.75
\n" ); document.write( "now the side which was 2 inches more, its length is:
\n" ); document.write( "x+2=8.75 + 2=10.75
\n" ); document.write( "and the third and the last which was twice of 'x':
\n" ); document.write( "2x = 2(8.75)=17.5
\n" ); document.write( "sides are:
\n" ); document.write( "8.75,10.75,17.5\r
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