document.write( "Question 636254: A solution of 61% bleach is to be mixed with a solution of 27% bleach to make 68 gallons of a 44% solution. How many gallons of each should be used?\r
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Algebra.Com's Answer #400967 by ankor@dixie-net.com(22740)\"\" \"About 
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A solution of 61% bleach is to be mixed with a solution of 27% bleach
\n" ); document.write( " to make 68 gallons of a 44% solution.
\n" ); document.write( " How many gallons of each should be used?
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\n" ); document.write( "Let x = amt of 61% bleach required
\n" ); document.write( "the resulting mixture is to be 68 gal, therefore:
\n" ); document.write( "(68-x) = amt of 27% solution required
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\n" ); document.write( "A typical mixture equation
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\n" ); document.write( ".61x + .27(68-x) = .44(68)
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\n" ); document.write( ".61x + 18.36 - .27x = 29.92
\n" ); document.write( ".61x - .27x = 29.92 - 18.36
\n" ); document.write( ".34x = 11.56
\n" ); document.write( "x = 11.56/.34
\n" ); document.write( "x = 34 gal of 61% solution
\n" ); document.write( "and
\n" ); document.write( "68 - 34 = 34 gal of 27% solution
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