Algebra.Com's Answer #400956 by MathLover1(20850)  You can put this solution on YOUR website! \r \n" );
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document.write( "the domain of is real numbers ( ) the roots of denominator ; as you already know, denominator could NOT be equal to zero. \r \n" );
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document.write( "To find out what they are, solve using quadratic formula:\r \n" );
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document.write( " | Solved by pluggable solver: Quadratic Formula | \n" );
document.write( "Let's use the quadratic formula to solve for x:
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document.write( " Starting with the general quadratic \n" );
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document.write( " the general solution using the quadratic equation is: \n" );
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document.write( " So lets solve ( notice , , and ) \n" );
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document.write( " Plug in a=1, b=-12, and c=3 \n" );
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document.write( " Negate -12 to get 12 \n" );
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document.write( " Square -12 to get 144 (note: remember when you square -12, you must square the negative as well. This is because .) \n" );
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document.write( " Multiply to get  \n" );
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document.write( " Combine like terms in the radicand (everything under the square root) \n" );
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document.write( " Simplify the square root (note: If you need help with simplifying the square root, check out this solver) \n" );
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document.write( " Multiply 2 and 1 to get 2 \n" );
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document.write( " So now the expression breaks down into two parts \n" );
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document.write( " or  \n" );
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document.write( " Now break up the fraction \n" );
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document.write( " or  \n" );
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document.write( " Simplify \n" );
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document.write( " or  \n" );
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document.write( " So the solutions are: \n" );
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document.write( " or  \n" );
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document.write( "So, all values of that are in the domain of are the solutions \r \n" );
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