document.write( "Question 636364: The function g is defined below.\r
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\n" ); document.write( " g(x)=(x-9)/(x^2-12x+3)
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\n" ); document.write( "Find all values of x that are NOT in the domain of g.\r
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Algebra.Com's Answer #400956 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "the domain of \"g%28x%29\" is \"all\" real numbers (\"R\") \"except\" the roots of denominator \"x%5E2-12x%2B3\"; as you already know, denominator could NOT be equal to zero. \r
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Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for x:

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\n" ); document.write( " Starting with the general quadratic
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\n" ); document.write( " \"ax%5E2%2Bbx%2Bc=0\"
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\n" ); document.write( " the general solution using the quadratic equation is:
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\n" ); document.write( " \"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"
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\n" ); document.write( " So lets solve \"x%5E2-12%2Ax%2B3=0\" ( notice \"a=1\", \"b=-12\", and \"c=3\")
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\n" ); document.write( " \"x+=+%28--12+%2B-+sqrt%28+%28-12%29%5E2-4%2A1%2A3+%29%29%2F%282%2A1%29\" Plug in a=1, b=-12, and c=3
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\n" ); document.write( " \"x+=+%2812+%2B-+sqrt%28+%28-12%29%5E2-4%2A1%2A3+%29%29%2F%282%2A1%29\" Negate -12 to get 12
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\n" ); document.write( " \"x+=+%2812+%2B-+sqrt%28+144-4%2A1%2A3+%29%29%2F%282%2A1%29\" Square -12 to get 144 (note: remember when you square -12, you must square the negative as well. This is because \"%28-12%29%5E2=-12%2A-12=144\".)
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\n" ); document.write( " \"x+=+%2812+%2B-+sqrt%28+144%2B-12+%29%29%2F%282%2A1%29\" Multiply \"-4%2A3%2A1\" to get \"-12\"
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\n" ); document.write( " \"x+=+%2812+%2B-+sqrt%28+132+%29%29%2F%282%2A1%29\" Combine like terms in the radicand (everything under the square root)
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\n" ); document.write( " \"x+=+%2812+%2B-+2%2Asqrt%2833%29%29%2F%282%2A1%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
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\n" ); document.write( " \"x+=+%2812+%2B-+2%2Asqrt%2833%29%29%2F2\" Multiply 2 and 1 to get 2
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\n" ); document.write( " So now the expression breaks down into two parts
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\n" ); document.write( " \"x+=+%2812+%2B+2%2Asqrt%2833%29%29%2F2\" or \"x+=+%2812+-+2%2Asqrt%2833%29%29%2F2\"
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\n" ); document.write( " Now break up the fraction
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\n" ); document.write( " \"x=%2B12%2F2%2B2%2Asqrt%2833%29%2F2\" or \"x=%2B12%2F2-2%2Asqrt%2833%29%2F2\"
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\n" ); document.write( " Simplify
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\n" ); document.write( " \"x=6%2Bsqrt%2833%29\" or \"x=6-sqrt%2833%29\"
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\n" ); document.write( " So the solutions are:
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\n" ); document.write( " \"x=6%2Bsqrt%2833%29\" or \"x=6-sqrt%2833%29\"
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\n" ); document.write( "\n" ); document.write( "So, all values of \"x\" that are \"NOT\" in the domain of \"g\" are the solutions \r
\n" ); document.write( "\n" ); document.write( "\"x=6%2Bsqrt%2833%29\" \"and\" \"x=6-sqrt%2833%29\"\r
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