document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=636347>Question 636347</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the perimeter of a square increases by 25% then its area increases by ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #400937 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=400937\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area of square=Side*Side or A=S^2---formula #1<BR>\n" );
document.write( "Perimeter of square=Side+Side+Side+Side or P=4S or S=P/4  formula #2<BR>\n" );
document.write( "Lets put the value of S from formula #2 into formula #1 and we get<BR>\n" );
document.write( "A(b)=(P/4)^2=P^2/16-----formula #3-- before the increase<BR>\n" );
document.write( "Now if we increase P by 25%, we get 1.25P<BR>\n" );
document.write( "A(a)=(1.25P)^2/16=1.562P^2/16----formula #4---after increase<BR>\n" );
document.write( "Looking at formula #4, we see that P^2/16=A(b); the area before the increase<BR>\n" );
document.write( "Sooooo  A(a)=1.56A(b) or the area after the perimeter is increased increases by 1.562 units\r<BR>\n" );
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document.write( "Hope this helps---ptaylor<BR>\n" );
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