document.write( "Question 636292: find the equation of the diameter of the circle x^2+y^2+6x-2y=6 which when produced passes through the point (1,-2).\r
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Algebra.Com's Answer #400866 by reviewermath(1029) $\"\"$ $\"About$

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The equation of the circle can be expressed as $\"%28x+%2B+3%29%5E2+%2B+%28y+-+1%29%5E2+=+16\"$ .
\n" ); document.write( "The center of the circle $\"%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2\"$ is (h,k) and the radius is r. Therefore, the center of the circle $\"%28x+%2B+3%29%5E2+%2B+%28y+-+1%29%5E2+=+16\"$ is (-3,1).\r
\n" ); document.write( "\n" ); document.write( "The slope of line joining (1,-2) and (-3,1) is
\n" ); document.write( " $\"m+=+%281-%28-2%29%29%2F%28-3-1%29+=+-3%2F4\"$
\n" ); document.write( "The equation of the diameter is
\n" ); document.write( " $\"+y+-+%28-2%29+=+%28-3%2F4%29%28x+-+1%29\"$
\n" ); document.write( "Answer: $\"highlight%28y+=+%28-3%2F4%29x+-+5%2F4%29\"$ \n" ); document.write( "

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