document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=636198>Question 636198</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (36a/3) x (9/6a) =\r<BR>\n" );
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document.write( "I got= 18a^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #400852 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10555)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=400852\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "(36a/3) x (9/6a) =\r<BR>\n" );
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document.write( "I got= 18a^2\r<BR>\n" );
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document.write( "The way you presented this problem, the \"36a\" is one of the numerators, and the \"6a\" is one of the denominators. If so, here's the easiest way to simplify the two fractional expressions:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2836a%2F3%29%289%2F6a%29 ALIGN=MIDDLE  ALT=\"%2836a%2F3%29%289%2F6a%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > ----- <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%286cross%2836a%29%2Fcross%283%29%29%283cross%289%29%2Fcross%286a%29%29 ALIGN=MIDDLE  ALT=\"%286cross%2836a%29%2Fcross%283%29%29%283cross%289%29%2Fcross%286a%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > ---- <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%2818%29 ALIGN=MIDDLE  ALT=\"highlight_green%2818%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Send comments and “thank-yous” to “D” at  MathMadEzy@aol.com </SPAN>\n" );
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