document.write( "Question 636096: 3(x+5)-2(y-1)=6
\n" ); document.write( "x+4(y+3)=13
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Algebra.Com's Answer #400764 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "3(x+5)-2(y-1)=6
\n" ); document.write( "x+4(y+3)=13\r
\n" ); document.write( "\n" ); document.write( "3x+15-2y+2=6
\n" ); document.write( "x+4y+ 12=13\r
\n" ); document.write( "\n" ); document.write( "3x-2y = -11 |multiplying 1st EQ by 2 and adding to the second
\n" ); document.write( " x+4y = 1
\n" ); document.write( " 7x = -21
\n" ); document.write( " x = -3 and y = 1 \"y+=+%281-%28-3%29%29%2F4\" \n" ); document.write( "
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