document.write( "Question 636108: Write the equation of a circle that has the center on the x-axis, a radius of 1, and passes through the point (((square root of 2)/2),((square root of 2)/2)). \n" ); document.write( "
Algebra.Com's Answer #400752 by lwsshak3(11628)\"\" \"About 
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Write the equation of a circle that has the center on the x-axis, a radius of 1, and passes through the point (((square root of 2)/2),((square root of 2)/2)).
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\n" ); document.write( "Equation of a circle: \"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\", (h,k)=(x,y) coordinates of center, r=radius
\n" ); document.write( "For given circle:
\n" ); document.write( "r^2=1
\n" ); document.write( "r=1
\n" ); document.write( "k==0
\n" ); document.write( "equation:
\n" ); document.write( "(x-h)^2+y^2=1
\n" ); document.write( "solve for h using coordinates of given point (√2/2, √2/2)
\n" ); document.write( "(√2/2-h)^2+(√2/2)^2=1
\n" ); document.write( "2/4-√2h+h^2+2/4=1
\n" ); document.write( "h^2-√2h+1=1
\n" ); document.write( "h^2-√2h=0
\n" ); document.write( "h(h-√2)=0
\n" ); document.write( "h=0 (reject, does not check)
\n" ); document.write( "h=√2
\n" ); document.write( "Equation: (x-√2)^2+y^2=1 \n" ); document.write( "
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