document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=58533>Question 58533</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle is twice as long as it is wide. If the length and width are each decreased by 4cm, the area is reduced by224cm squared.  Find the dimensions of the original rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #40074 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=40074\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=2W<BR>\n" );
document.write( "(2W-4)*(W-4)=2W*W-224<BR>\n" );
document.write( "THUS<BR>\n" );
document.write( "2W^2-12W+16=2W^2-224<BR>\n" );
document.write( "2W^2-2W^2-12W+16=224=0<BR>\n" );
document.write( "-12W+240=0<BR>\n" );
document.write( "-W+20=0<BR>\n" );
document.write( "-W=-20<BR>\n" );
document.write( "W=20 IS THE WIDTH<BR>\n" );
document.write( "L=2*20<BR>\n" );
document.write( "L=40 IS THE LENGTH<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "(40-4)(20-4)=40*20-224<BR>\n" );
document.write( "36*16=800-224<BR>\n" );
document.write( "576=576\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );