document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=635898>Question 635898</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 15x^2+2x=56 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #400663 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=400663\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Firstly you want to rewrite the equation into the standard quadratic form<BR>\n" );
document.write( "  15x^2 + 2x - 56 = 0<BR>\n" );
document.write( "Because of the coefficient of x^2 and the multiple factors of 56, only the brainiacs can quickly factor this quadratic. I recommend the tried and true method of factoring it - the quadratic equation (I also named this the Markconian Equation - after one of my students). \r<BR>\n" );
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document.write( " x1,2 =(-b +/-sqrt(b^2-4*a*c))/(2*a)\r<BR>\n" );
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document.write( "where a = 15, b = 2, c = -56\r<BR>\n" );
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document.write( "Applying the quadratic equation yield the two roots of the given quadratic; <BR>\n" );
document.write( "   x1,x2 = 56/30,-60/30<BR>\n" );
document.write( "Based on the roots x1 and x2, the original quadratic factors into<BR>\n" );
document.write( "   a*(x-x1)(x-x2)<BR>\n" );
document.write( "In our case we have<BR>\n" );
document.write( "   15*(x - 56/60)(x + 60/30)<BR>\n" );
document.write( "Multiply the first parenthetical expression by 15 and using 60/30 = 2 we get the final factored form of the given quadratic\r<BR>\n" );
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document.write( "    (15x - 28)(x + 2) = 15x^2 + 2x  - 56  </SPAN>\n" );
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