document.write( "Question 635926: Help please?!\r
\n" ); document.write( "\n" ); document.write( "SOLVE THE SYSTEM:\r
\n" ); document.write( "\n" ); document.write( "2/x+3/y-2/z=-1\r
\n" ); document.write( "\n" ); document.write( "3/x-18/y+5/z=4\r
\n" ); document.write( "\n" ); document.write( "5/x+3/y-1/z=1
\n" ); document.write( "

Algebra.Com's Answer #400659 by DrBeeee(684)\"\" \"About 
You can put this solution on YOUR website!
The inverse of variables is turning you up side down! Fix it!
\n" ); document.write( "Merely let a = 1/x, b = 1/y and c = 1/z and yield the friendly 3x3 system of equations
\n" ); document.write( " 2a + 3b - 2c = -1
\n" ); document.write( " 3a - 18b + 5c = 4
\n" ); document.write( " 5a + 3b - c = 1
\n" ); document.write( "Use Mathcad or your handy dandy TI-84 to get a, b and c. Then just get their inverse to get x, y, and z. You can also solve \"by hand\" using the inverse of a 3x3 matrix.
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