document.write( "Question 635926: Help please?!\r
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document.write( "SOLVE THE SYSTEM:\r
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document.write( "2/x+3/y-2/z=-1\r
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document.write( "3/x-18/y+5/z=4\r
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document.write( "5/x+3/y-1/z=1 \n" );
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Algebra.Com's Answer #400659 by DrBeeee(684)![]() ![]() ![]() You can put this solution on YOUR website! The inverse of variables is turning you up side down! Fix it! \n" ); document.write( "Merely let a = 1/x, b = 1/y and c = 1/z and yield the friendly 3x3 system of equations \n" ); document.write( " 2a + 3b - 2c = -1 \n" ); document.write( " 3a - 18b + 5c = 4 \n" ); document.write( " 5a + 3b - c = 1 \n" ); document.write( "Use Mathcad or your handy dandy TI-84 to get a, b and c. Then just get their inverse to get x, y, and z. You can also solve \"by hand\" using the inverse of a 3x3 matrix. \n" ); document.write( " |