document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=635904>Question 635904</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 4cm more than the width and the perimeter is at least 48 cm . what are the smallest possible dimensions for the rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #400628 by </B><A HREF=/tutors/aboutme.mpl?userid=graphmatics><B>graphmatics(170)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=graphmatics><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=graphmatics><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=400628\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let w be the width then w+4 is the length and 2*w+2*(w+4)=4*w+8 is the expression for the perimeter. So<BR>\n" );
document.write( "4*w+8>=48<BR>\n" );
document.write( "4*w>=40<BR>\n" );
document.write( "w>=10  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );