document.write( "Question 635690: The age of a father was 6 times the age of his son two years ago. After six years the ratio of their ages was 10:3. what is the age of father now? \n" ); document.write( "
Algebra.Com's Answer #400601 by ankor@dixie-net.com(22740)\"\" \"About 
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The age of a father was 6 times the age of his son two years ago.
\n" ); document.write( " After six years the ratio of their ages was 10:3.
\n" ); document.write( " what is the age of father now?
\n" ); document.write( ":
\n" ); document.write( "Let f = father's present age
\n" ); document.write( "let s = son's age
\n" ); document.write( ":
\n" ); document.write( "\"The age of a father was 6 times the age of his son two years ago.\"
\n" ); document.write( "f - 2 = 6(s - 2)
\n" ); document.write( "f - 2 = 6s - 12
\n" ); document.write( "f = 6s - 12 + 2
\n" ); document.write( "f = 6s - 10
\n" ); document.write( ":
\n" ); document.write( "\"After six years the ratio of their ages was 10:3.\"
\n" ); document.write( "\"%28f%2B6%29%2F%28s%2B6%29\" = \"10%2F3\"
\n" ); document.write( "cross multiply
\n" ); document.write( "10(s+6) = 3(f+6)
\n" ); document.write( "10s + 60 = 3f + 18
\n" ); document.write( "10s + 60 - 18 = 3f
\n" ); document.write( "10s + 42 = 3f
\n" ); document.write( "Replace f with (6s-10)
\n" ); document.write( "10s + 42 = 3(6s-10)
\n" ); document.write( "10s + 42 = 18s - 30
\n" ); document.write( "42 + 30 = 18s - 10s
\n" ); document.write( "72 = 8s
\n" ); document.write( "s = 72/8
\n" ); document.write( "s = 9 yrs is the son's age
\n" ); document.write( "then
\n" ); document.write( "f = 6s - 10
\n" ); document.write( "f = 6(9) - 10
\n" ); document.write( "f = 54 - 10
\n" ); document.write( "f = 44 yrs is the father's age
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\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Confirm that
\n" ); document.write( "\"%2844%2B6%29%2F%289%2B6%29\" = \"50%2F15\" = \"10%2F3\"
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