document.write( "Question 635690: The age of a father was 6 times the age of his son two years ago. After six years the ratio of their ages was 10:3. what is the age of father now? \n" ); document.write( "
Algebra.Com's Answer #400601 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The age of a father was 6 times the age of his son two years ago. \n" ); document.write( " After six years the ratio of their ages was 10:3. \n" ); document.write( " what is the age of father now? \n" ); document.write( ": \n" ); document.write( "Let f = father's present age \n" ); document.write( "let s = son's age \n" ); document.write( ": \n" ); document.write( "\"The age of a father was 6 times the age of his son two years ago.\" \n" ); document.write( "f - 2 = 6(s - 2) \n" ); document.write( "f - 2 = 6s - 12 \n" ); document.write( "f = 6s - 12 + 2 \n" ); document.write( "f = 6s - 10 \n" ); document.write( ": \n" ); document.write( "\"After six years the ratio of their ages was 10:3.\" \n" ); document.write( " \n" ); document.write( "cross multiply \n" ); document.write( "10(s+6) = 3(f+6) \n" ); document.write( "10s + 60 = 3f + 18 \n" ); document.write( "10s + 60 - 18 = 3f \n" ); document.write( "10s + 42 = 3f \n" ); document.write( "Replace f with (6s-10) \n" ); document.write( "10s + 42 = 3(6s-10) \n" ); document.write( "10s + 42 = 18s - 30 \n" ); document.write( "42 + 30 = 18s - 10s \n" ); document.write( "72 = 8s \n" ); document.write( "s = 72/8 \n" ); document.write( "s = 9 yrs is the son's age \n" ); document.write( "then \n" ); document.write( "f = 6s - 10 \n" ); document.write( "f = 6(9) - 10 \n" ); document.write( "f = 54 - 10 \n" ); document.write( "f = 44 yrs is the father's age \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Confirm that \n" ); document.write( " |