document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=635874>Question 635874</A>: <I><SPAN STYLE=\"word-break: break-all;\"> use the given zero to find the remaining zeros of the function f(x) = x^3 - 3x^2 + 25x - 75; zero: 5 i </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #400597 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=400597\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  use the given zero to find the remaining zeros of the function f(x) = x^3 - 3x^2 + 25x - 75; zero: 5 i<BR>\n" );
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document.write( "Fact: Since the coefficients are Real, -5i is also a zero.<BR>\n" );
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document.write( "Therefore (x-5i)(x+5i) = x^2+25 must be a factor of f(x)<BR>\n" );
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document.write( "Rewrite:<BR>\n" );
document.write( "x^2(x-3)+25(x-3) = 9<BR>\n" );
document.write( "(x-3)(x^2+25) = 0<BR>\n" );
document.write( "x = 3 or x = 5i or x = -5i<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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