document.write( "Question 635813: 60 ml of solution A is mixed with 120 ml of solution B to produce solution C which contains 8% of pure acid. If 80 ml of solution A is mixed with 40 ml of solution B, a solution D containing 10% of pure acid can be produced. Find the percentage of pure acid in solution A. \n" ); document.write( "
Algebra.Com's Answer #400577 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! 60 ml of solution A is mixed with 120 ml of solution B to produce solution C which contains 8% of pure acid. If 80 ml of solution A is mixed with 40 ml of solution B, a solution D containing 10% of pure acid can be produced. Find the percentage of pure acid in solution A. \n" ); document.write( "** \n" ); document.write( "let x=% acid in solution A \n" ); document.write( "let y=% acid in solution B \n" ); document.write( "2 equations: \n" ); document.write( "60x+120y=.08(60+120)=.08(180)=14.4 \n" ); document.write( "80x+40y=.10(80+40)=.10(120)=12 \n" ); document.write( ".. \n" ); document.write( "60x+120y=14.4 \n" ); document.write( "80x+40y=12 \n" ); document.write( ".. \n" ); document.write( "60x+120y=14.4 \n" ); document.write( "240x+120y=36 \n" ); document.write( "subtract \n" ); document.write( "-180x=-21.6 \n" ); document.write( "x=21.6/180=.12 \n" ); document.write( "40y=12-80x=12-.12*80=2.4 \n" ); document.write( "y=2.4/40=.06 \n" ); document.write( "percentage of pure acid in solution A=12% \n" ); document.write( " \n" ); document.write( " |