document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=635780>Question 635780</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a train leaves a station and travel north at a speed 45 mph.four hours later a second train leaves on a parallel trick and travel north at 105 mph.how far from station will they meet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #400568 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=400568\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The first train went 4*45=180 in four hours. <BR>\n" );
document.write( "The second train gains 60 miles every hour.<BR>\n" );
document.write( "180/60=3 hours to catch up<BR>\n" );
document.write( "3*105=305 miles from the station.\r<BR>\n" );
document.write( "\n" );
document.write( "check3*45=135<BR>\n" );
document.write( "135+180=305<BR>\n" );
document.write( "ok </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );