document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=635819>Question 635819</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the coordinates of the vertex for the parabola given by the equation f(x)=-x^2-2x-1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #400565 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=400565\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the coordinates of the vertex for the parabola given by the equation f(x)=-x^2-2x-1<BR>\n" );
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document.write( "Find the coordinates of the vertex for the parabola given by the equation <BR>\n" );
document.write( "f(x)=-3x^2-x-1.<BR>\n" );
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document.write( "The vertex is on the LOS, Line of Symmetry, or the Axis of Symmetry<BR>\n" );
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document.write( "The LOS is x = -b/2a<BR>\n" );
document.write( "x = 1/-6 = -1/6<BR>\n" );
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document.write( "f(-1/6) = -1/12 + 1/6 - 1 = -11/12<BR>\n" );
document.write( "--> vertex (-1/6,-11/12)\r<BR>\n" );
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