document.write( "Question 7235: Solve for x, y, and z in the following system of equations.
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\n" ); document.write( " x + 2y + z = 2
\n" ); document.write( " 5x = z
\n" ); document.write( " y = -2x\r
\n" ); document.write( "\n" ); document.write( "Any help is appreciated. Thank you in advance!
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Algebra.Com's Answer #4005 by bonster(299)\"\" \"About 
You can put this solution on YOUR website!
x+2y+z=2\r
\n" ); document.write( "\n" ); document.write( "1) Substitute y as -2x
\n" ); document.write( "x + \"2%28-2x%29\"+z=2\r
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\n" ); document.write( "\n" ); document.write( "2) Substitute z as 5x
\n" ); document.write( "x+ 2(-2x) + \"5x\"=2\r
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\n" ); document.write( "\n" ); document.write( "3) x+(-4x)+5x=2\r
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\n" ); document.write( "\n" ); document.write( "4) -3x+5x=2\r
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\n" ); document.write( "\n" ); document.write( "5) 2x=2\r
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\n" ); document.write( "\n" ); document.write( "6) \"2x%2F2\"=\"2%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "7) x=1\r
\n" ); document.write( "\n" ); document.write( "8) Since y=-2x, (-2)(1)=-2\r
\n" ); document.write( "\n" ); document.write( "9) Since z=5x, (5)(1)=5\r
\n" ); document.write( "\n" ); document.write( "x=1, y=-2, z=5
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