document.write( "Question 7235: Solve for x, y, and z in the following system of equations.
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document.write( " x + 2y + z = 2
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document.write( " 5x = z
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document.write( " y = -2x\r
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document.write( "Any help is appreciated. Thank you in advance! \n" );
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Algebra.Com's Answer #4005 by bonster(299)![]() ![]() ![]() You can put this solution on YOUR website! x+2y+z=2\r \n" ); document.write( "\n" ); document.write( "1) Substitute y as -2x \n" ); document.write( "x + \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2) Substitute z as 5x \n" ); document.write( "x+ 2(-2x) + \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3) x+(-4x)+5x=2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4) -3x+5x=2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5) 2x=2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "6) \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "7) x=1\r \n" ); document.write( "\n" ); document.write( "8) Since y=-2x, (-2)(1)=-2\r \n" ); document.write( "\n" ); document.write( "9) Since z=5x, (5)(1)=5\r \n" ); document.write( "\n" ); document.write( "x=1, y=-2, z=5 \n" ); document.write( " |