document.write( "Question 635716: A can do half as much work as B in the same time and B can do one third as much work as C. If they can finish the work in 12 days, find in how many days can each finish the work.
\n" ); document.write( "Solution:
\n" ); document.write( " Let C does 1 work in x days, then
\n" ); document.write( "C = 1/x, B = 1/3x, A = 1/16x
\n" ); document.write( "Total work = 1
\n" ); document.write( "or, 12(1/x + 1/3x + 1/6x) = 1
\n" ); document.write( "Or, x = 1/18
\n" ); document.write( "So, C = 18 days, B = 54 days, C = 108 days. Am I right ? I am not sure. \n" ); document.write( "

Algebra.Com's Answer #400499 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "Let C does 1 work in x days, then
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document.write( " C = 1/x, B = 1/3x, A = 1/6x
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document.write( " Total work = 1
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document.write( " or, 12(1/x + 1/3x + 1/6x) = 1
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document.write( "prefer to think of it in this manner: work/day
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document.write( " (1/x + 1/3x + 1/6x) = 1/12    |Multiplying thru by 12x so as all denominators = 1
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document.write( " 12 + 4 + 2 = x
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document.write( " Or, x = 18
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document.write( " So, C = 18 days, B = 54 days, C = 108 days   Yes. Good Work. \n" );
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