document.write( "Question 635705: if 200 kg of ration lasts 3 months for 4 boys,how many boys will consume 650 of the ration in the same period? \n" ); document.write( "
Algebra.Com's Answer #400488 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! if 200 kg of ration lasts 3 months for 4 boys,how many boys will consume 650 of the ration in the same period? \n" ); document.write( "--- \n" ); document.write( "# of boys is directly related to amount of ration and indirectly \n" ); document.write( "related to amount of time. \n" ); document.write( "--- \n" ); document.write( "b = k*r/t \n" ); document.write( "--- \n" ); document.write( "Solve for \"k\" using \"200 kg of ration lasts 3 months for 4 boys\". \n" ); document.write( "4 = k*200/3 \n" ); document.write( "k = 12/200 = 0.06 \n" ); document.write( "====================== \n" ); document.write( "Equation: \n" ); document.write( "b = 0.06*r/t \n" ); document.write( "---- \n" ); document.write( "how many boys will consume 650 of the ration in the same period? \n" ); document.write( "b = 0.06*650/3 \n" ); document.write( "b = 13 (# of boys needed) \n" ); document.write( "============================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================ \n" ); document.write( " \n" ); document.write( " |