document.write( "Question 635677: a father is now 3 times as old as his son. twelve years ago, he was six times as old as his son. find the present age of each \n" ); document.write( "
Algebra.Com's Answer #400481 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Present age of of Father = f years old
\n" ); document.write( "Present age of Son = s years old\r
\n" ); document.write( "\n" ); document.write( "Father is 3 times as old as his son
\n" ); document.write( "f=3s...............(1)
\n" ); document.write( "12 years ago
\n" ); document.write( "father was = f-12 years old
\n" ); document.write( "Son was = s-12 years old
\n" ); document.write( "Then
\n" ); document.write( "f-12=6(s-12)
\n" ); document.write( "f-12=6s-72
\n" ); document.write( "f=6s-72+12
\n" ); document.write( "f=6s-60..............(2)
\n" ); document.write( "Compare (1) and (2)
\n" ); document.write( "3s=6s-60
\n" ); document.write( "3s-6s=-60
\n" ); document.write( "-3s=-60
\n" ); document.write( "-3s/-3=-60/-3
\n" ); document.write( "s=20
\n" ); document.write( "Put the value of s in (1)
\n" ); document.write( "f=3s
\n" ); document.write( "f=3(20)
\n" ); document.write( "f=60\r
\n" ); document.write( "\n" ); document.write( "Present age of of Father = f = 60 years old
\n" ); document.write( "Present age of Son = s = 20 years old\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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