document.write( "Question 635660: the sum of the ages of two brothers is 20. in fiveyears, one is twice the other. find the present ages of the two brothers \n" ); document.write( "
Algebra.Com's Answer #400469 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Present age of DISABLED_event_One= a
\n" ); document.write( "Present age of Other = b\r
\n" ); document.write( "\n" ); document.write( "Sum of the age is 20
\n" ); document.write( "a+b = 20 .................(1)\r
\n" ); document.write( "\n" ); document.write( "In Fiver years
\n" ); document.write( "One will be = a+5 years old
\n" ); document.write( "Other will be = b+5 years old
\n" ); document.write( "Then
\n" ); document.write( "One is twice the other
\n" ); document.write( "a+5=2(b+5)
\n" ); document.write( "a+5=2b+10
\n" ); document.write( "a=2b+10-5
\n" ); document.write( "a=2b+5......................(2)
\n" ); document.write( "Put the value of a in (1)
\n" ); document.write( "2b+5+b = 20
\n" ); document.write( "3b+5=20
\n" ); document.write( "3b=20-5
\n" ); document.write( "3b=15
\n" ); document.write( "3b/3=15/3
\n" ); document.write( "b=15
\n" ); document.write( "Put the value of b in (1)
\n" ); document.write( "a+b=20.........(1)
\n" ); document.write( "a+15=20
\n" ); document.write( "a=20-15
\n" ); document.write( "a=5\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Present age of DISABLED_event_One= a = 5 years old
\n" ); document.write( "Present age of Other = b = 15 years old\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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