document.write( "Question 635634: A total of 1700 in two mutual funds. One earned 6% the other earned 3% A profit of 60 dollars was earned. How much was invested in each mutual fund \n" ); document.write( "

Algebra.Com's Answer #400446 by mananth(16946) $\"\"$ $\"About$

You can put this solution on YOUR website!
Account I6.00% per annum ------------- Amount invested =x
\n" ); document.write( "Account II3.00% per annum ------------ Amount invested = y
\n" ); document.write( " 1700
\n" ); document.write( "Interest----- 60
\n" ); document.write( "
\n" ); document.write( "Account I 6.00% per annum ---x
\n" ); document.write( "Account II 3.00% per annum ---y
\n" ); document.write( "
\n" ); document.write( "x + 1 y= 1700 -------------1
\n" ); document.write( "
\n" ); document.write( "6.00% x + 3.00% y= 60
\n" ); document.write( "Multiply by 100
\n" ); document.write( "6 x + 3 y= 6000.00 --------2
\n" ); document.write( "Multiply (1) by -6
\n" ); document.write( "we get
\n" ); document.write( "-6 x -6 y= -10200.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x -3 y= -4200
\n" ); document.write( "divide by -3
\n" ); document.write( " y = 1400
\n" ); document.write( "Account I 6.00% $ 300
\n" ); document.write( "Account II 3.00% $ 1400
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "300 --------- 6.00% ------- 18.00
\n" ); document.write( "1400 ------------- 3.00% ------- 42.00
\n" ); document.write( "Total -------------------- 60.00
\n" ); document.write( "
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( " \n" ); document.write( "

\n" );