document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=58419>Question 58419</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The question in the book asks:  Use substitution to solve the linear system.  \r<BR>\n" );
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document.write( "0.25x - 1.25y = 10.25<BR>\n" );
document.write( "x - 5y = 20\r<BR>\n" );
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document.write( "My x and y's both cancel out or equal zero.  I don't understand.\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #40044 by </B><A HREF=/tutors/aboutme.mpl?userid=babynarah2007><B>babynarah2007(12)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=babynarah2007><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=40044\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The question in the book asks: Use substitution to solve the linear system. <BR>\n" );
document.write( "0.25x - 1.25y = 10.25<BR>\n" );
document.write( "x - 5y = 20 <BR>\n" );
document.write( "My x and y's both cancel out or equal zero. I don't understand. <BR>\n" );
document.write( "Thanks<BR>\n" );
document.write( "0.25x - 1.25y = 10.25<BR>\n" );
document.write( "            x = 10.25/0.25 + 1.25y/0.25<BR>\n" );
document.write( "            x = 41 + 5y<BR>\n" );
document.write( "       we can define this equation : x - 5y = 41 (not)x - 5y = 20<BR>\n" );
document.write( "           so, 0.25(41+5y)-1.25y = 10.25<BR>\n" );
document.write( "                10.25 + 1.25y - 1.25y = 10.25<BR>\n" );
document.write( "                  <BR>\n" );
document.write( "            Both X and Y are null set, because they were cancelled out.<BR>\n" );
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