document.write( "Question 635620: \"The population of a certain city was 30,000 in 1980 and 40,500 in 1990. If the formula y=Po(e^ht) applies to the growth citys population, what is the population projected to be in the year 2010?\"\r
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document.write( "not sure how to set up the information for the equation \n" );
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Algebra.Com's Answer #400429 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You start with \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You know the starting population, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Fortunately, we are given another data point, specifically the population in 1990, and using this, we can solve the equation for \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide by 30,000:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Take the natural log of both sides. Actually, you could take the log to any base, as long as it is the same base on both sides of the equation, but because the equation involves \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now use \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to write:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then use \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(See what I mean about simpler arithmetic?)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Which the calculator says is close enough to 0.03 that the difference doesn't matter.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "NOW, you go back to the original function:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plug in the numbers\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "And do the arithmetic. I'll let you run the calculator this time. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |