document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=635387>Question 635387</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man walks a certain distance at the rate of 5 miles an hour and returns at the rate of 4 miles an hour. If the total time that it takes is 3 hours and 9 minute, what is the total distance that he walks? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #400331 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=400331\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r<BR>\n" );
document.write( "Let d=distance walked one way; 2d=total distance walked<BR>\n" );
document.write( "Time walking at 5 mi/hr=d/5<BR>\n" );
document.write( "Time walking at 4 mi/hr=d/4\r<BR>\n" );
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document.write( "And we are told that the above times add up to 3 3/20 hr.<BR>\n" );
document.write( "3 3/20 hr=63/20 hr<BR>\n" );
document.write( "So our equation to solve is:<BR>\n" );
document.write( "d/5 +d/4=63/20  multiply each term by 20<BR>\n" );
document.write( "4d+5d=63 <BR>\n" );
document.write( "9d=63<BR>\n" );
document.write( "d=7 mi<BR>\n" );
document.write( "2d = total distance walked =2*7=14 mi---ans\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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