document.write( "Question 635434: the length of a rectangle is 8 ft. longer than the width. Which has the same dimension as the side of a square . if the area of the rectangle is equal to 160 square feet more than the area of the square. What are the length and width of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #400329 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Area of Rectangle (A)=Length(L)*Width(W) or A(Rectangle)=LW \n" ); document.write( "Area of a Square (A)=Side(S)* Side(S) or A(square)=S^2 \n" ); document.write( "Let W=width of rectangle which is also the length of the side of a square \n" ); document.write( "Then the length,L, of the rectangle=W+8 \n" ); document.write( "Area, A, of rectangle=W(W+8) \n" ); document.write( "Area of Square=W^2 \n" ); document.write( "Now we are told the following: \n" ); document.write( "W^2+160=W(W+8) simplify \n" ); document.write( "W^2+160=W^2+8W collect like terms (W^2's cancel out) \n" ); document.write( "8W=160 \n" ); document.write( "W=20 ft------------------width of rectangle \n" ); document.write( "W+8=20+8=28 ft----Length of rectangle \n" ); document.write( "CK \n" ); document.write( "20*28=20*20+160 \n" ); document.write( "560=400+160 \n" ); document.write( "560=560\r \n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor \n" ); document.write( " |