document.write( "Question 635420: Twenty-six small communities in Connecticut (population near 10,000 each) gave an average of x = 138.5 reported cases of larceny per year. Assume that σ is known to be 44.5 cases per year.
\n" ); document.write( " (a) Find a 90% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (Round your answers to one decimal place.)
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\n" ); document.write( "\n" ); document.write( "(b) Find a 95% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (Round your answers to one decimal place.) \r
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\n" ); document.write( "\n" ); document.write( "(c) Find a 99% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (Round your answers to one decimal place.) \r
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Algebra.Com's Answer #400318 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( "Note: z-values for various confidence levels
\n" ); document.write( "90% z = 1.645
\n" ); document.write( "95% z = 1.96
\n" ); document.write( "98% z = 2.33
\n" ); document.write( "99% z = 2.576
\n" ); document.write( "a) ME = 1.645(44.5/sqrt(10000)= .732
\n" ); document.write( " 138.5 - ME < \"mu\" < 138.5 + ME
\n" ); document.write( "b)ME = 1.96(44.5/sqrt(10000)= .873
\n" ); document.write( " 138.5 - ME < \"mu\" < 138.5 + ME
\n" ); document.write( "c)ME = 2.576(44.5/sqrt(10000)= 1.146
\n" ); document.write( " 138.5 - ME < \"mu\" < 138.5 + ME \n" ); document.write( "
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