document.write( "Question 58433: Supppose 2000 bacteria are present at time t=0. Then t minutes later, the number of bacteria present will be (N)t=2000(2)^t/40\r
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document.write( "Find the number of bacteria present after 20 and 120 minutes.\r
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document.write( "Round to the nearest whole number for each one. \n" );
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Algebra.Com's Answer #40030 by Nate(3500) ![]() You can put this solution on YOUR website! (N)t = 50(2)^t \n" ); document.write( "After 20 minutes: \n" ); document.write( "(N)t = 50(2)^20 = 52,428,800 \n" ); document.write( "After 120 minutes: \n" ); document.write( "(N)t = 50(2)^t = 6.6461399789245793645190353014017 x 10^37 \n" ); document.write( "or: 66,461,399,789,245,793,645,190,353,014,017,000,000 \n" ); document.write( " |