document.write( "Question 635390: Two automobiles set out simultaneously from places 100 miles apart . They traveled toward each other and passed at the end of 1 hour and 40 minutes. The speed of one automobile was 5 miles per hour greater than that of the other. Find the speed of each? \n" ); document.write( "
Algebra.Com's Answer #400283 by AnlytcPhil(1806)\"\" \"About 
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document.write( "The slower traveled at x miles per hour\r\n" );
document.write( "The faster traveled at x+5 miles per hour\r\n" );
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document.write( "Their approach rate = the sum of their speeds = x+(x+5) = x+x+5 = 2x+5\r\n" );
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document.write( "Time = 1 hour 40 minutes = \"1%2640%2F60\" hours = \"1%262%2F3\" hours = \"5%2F3\" hours.\r\n" );
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document.write( "Distance = (Rate)·(Time)\r\n" );
document.write( "     100 = (2x+5)·\"5%2F3\"\r\n" );
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document.write( "Multiply through by 3\r\n" );
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document.write( "     300 = (2x+5)·5\r\n" );
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document.write( "Divide both sides by 5\r\n" );
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document.write( "      60 = 2x+5\r\n" );
document.write( "      55 = 2x\r\n" );
document.write( "    27.5 = x\r\n" );
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document.write( "The slower was going 27.5 miles per hour and the faster was going\r\n" );
document.write( "5 miles per hour faster or 32.5 miles per hour.\r\n" );
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document.write( "Edwin
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