document.write( "Question 635359: A 20-gallon salt-water solution contains 15% pure salt. How much water should be added to make a new solution that is only 12% salt? \n" ); document.write( "
Algebra.Com's Answer #400269 by Maths68(1474)\"\" \"About 
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Solution A
\n" ); document.write( "Amount=20 gallons
\n" ); document.write( "Concentration =15%=0.15\r
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\n" ); document.write( "\n" ); document.write( "Solution B
\n" ); document.write( "Amount=x gallons
\n" ); document.write( "Concentration =0%=0 (Pure Water)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Mixture
\n" ); document.write( "Amount=(20+x)gallons
\n" ); document.write( "Concentration =12%=0.12\r
\n" ); document.write( "\n" ); document.write( "(Amount of Solution A)(Concentration of Solution B)+(Amount of Solution B)(Concentration of Solution A)=(Amount of Mixture)(Concentration of Mixture
\n" ); document.write( "(20)(0.15)+(x)(0)=(20+x)(0.12)
\n" ); document.write( "3+0=2.4+0.12x
\n" ); document.write( "3-2.4=0.12x
\n" ); document.write( "0.6=0.12x
\n" ); document.write( "0.6/0.12=0.12x/0.12
\n" ); document.write( "5=x
\n" ); document.write( "x=5\r
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\n" ); document.write( "\n" ); document.write( "A 20-gallon salt-water solution contains 15% pure salt. 5 gallons of water should be added to make a new solution that is only 12% salt.
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