document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=635328>Question 635328</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the method of substitution to solve the system of linear equations.\r<BR>\n" );
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document.write( "4x-y=5<BR>\n" );
document.write( "9x-2x=14 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #400252 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=400252\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4x-y=5<BR>\n" );
document.write( "9x-2x=14<BR>\n" );
document.write( "7x=14<BR>\n" );
document.write( "/7<BR>\n" );
document.write( "x=2\r<BR>\n" );
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document.write( "substitute x=2 in first equation\r<BR>\n" );
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document.write( "4x-5=5<BR>\n" );
document.write( "4*2-y=5<BR>\n" );
document.write( "8-y=5\r<BR>\n" );
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document.write( "-y=-8+5<BR>\n" );
document.write( "-y=-3<BR>\n" );
document.write( "/-1<BR>\n" );
document.write( "y=3\r<BR>\n" );
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document.write( "x=2,y=3 </SPAN>\n" );
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