document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=635269>Question 635269</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Pressure varies inversely as volume. When the pressure is 16 pascals, the volume is 84 liters. What would the volume be if the pressure is reduced to 12 pascals?\r<BR>\n" );
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document.write( "The equation I used is P = k/V   (P stands for pressure, V for volume.)\r<BR>\n" );
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document.write( "Plug in the values and get 16 = k/84, which simplifies to k= 1344. \r<BR>\n" );
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document.write( "After that, you take P = k/V again and plug in P and k for this equation: <BR>\n" );
document.write( "12 = 1344/V\r<BR>\n" );
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document.write( "I know that V is equal to 112 but how do you solve for V? Can you show me the steps?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #400206 by </B><A HREF=/tutors/aboutme.mpl?userid=asuar010><B>asuar010(338)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=asuar010><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=asuar010><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=400206\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> very simple first you multiply the last equation completely by V and you get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12V=1344 ALIGN=MIDDLE  ALT=\"12V=1344\"   DISABLED_style= \"max-width:90%; height:auto;\" > and then we just divide both sides by 12 and we get V=112 </SPAN>\n" );
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