document.write( "Question 635190: I was asked to calculate the area of a rhombus split into two triangles. The triangles were equilateral and it gave me two sides that were both 6. I understand I can use Heron's formula for this, but I came across a part in this certain problem I didn't understand. So, first I do S=one-half (6+6+6). It is 9. Then, you do s(9-6)(9-6)(9-6) and square it. They put the answer as 9 and a squared 3 where its under the little house thing. How did they get from 9(3)(3)(3)squared to that?! \n" ); document.write( "
Algebra.Com's Answer #400162 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Heron's formula is:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Where did you get the idea that you have to square , since means take the square root?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Just multiply it out and then take the square root. You have 5 factors of 3, which you can write as 81 times 3. The square root of 81 is 9 and the square root of 3 is . Don't forget to double your answer since it takes two of these triangles to make your rhombus. And oh by the way, \"the little house thing\" is called a radical.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "John
\n" ); document.write( "
\n" ); document.write( "My calculator said it, I believe it, that settles it
\n" ); document.write( "
\"The

\n" ); document.write( "
\n" ); document.write( "
\n" );