document.write( "Question 635208: if chase does a job in 15 hours less time than jacqeline, and they can do the job together in 4 hours, how long will it take each to the job alone? \n" ); document.write( "
Algebra.Com's Answer #400151 by ptaylor(2198)\"\" \"About 
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Let x=time it takes Jacqueline to do the job alone
\n" ); document.write( "So Jacqueline works at the rate of 1/x of the job per hour
\n" ); document.write( "Then x-15 =time it takes Chase to do the job alone
\n" ); document.write( "And Chase works at the rate of 1/(x-15) of the job per hour
\n" ); document.write( "Together they work at the rate of 1/x + 1/(x-15) of the job per hour
\n" ); document.write( "But we are told that they can do the job, working together, in 4 hours
\n" ); document.write( "So together they work at the rate of 1/4 of the job per hour
\n" ); document.write( "Then our equation to solve is:
\n" ); document.write( "1/x + 1/(x-15)=1/4 multiply each term by 4x(x-15)
\n" ); document.write( "4(x-15)+4x=x(x-15) simplify
\n" ); document.write( "4x-60+4x=x^2-15x collect like terms
\n" ); document.write( "x^2-23x+60=0 quadratic in standard form and it can be factored
\n" ); document.write( "(x-20)(x-3)=0
\n" ); document.write( "x=20 hours---Time it takes Jacqueline to do the job working alone
\n" ); document.write( "x-15=20-15=5 hours-----Time it takes Chase to do the job working alone
\n" ); document.write( "and
\n" ); document.write( "x=3 hours---- IMPOSSIBLE ANSWER---WHY????
\n" ); document.write( "CK
\n" ); document.write( "1/20+1/5=1/4
\n" ); document.write( "1/20+4/20=1/4
\n" ); document.write( "5/20=1/4
\n" ); document.write( "1/4=1/4\r
\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor \n" ); document.write( "
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