document.write( "Question 635050: The width of a rectangle is 3 ft. less than the length. The area is 4 ft^2. Find the length and the width.\r
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document.write( "For some reason I cannot figure this out and I need it for a test can anyone help quickly \n" );
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Algebra.Com's Answer #400063 by Maths68(1474) You can put this solution on YOUR website! Length =L \n" ); document.write( "Width=W=L-3 \n" ); document.write( "Area=A=4ft^2\r \n" ); document.write( "\n" ); document.write( "Area= Length*Width \n" ); document.write( "A=L*W \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Solve for L \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so L=4\r \n" ); document.write( "\n" ); document.write( "Length =L = 4 ft \n" ); document.write( "Width=W=L-3 = 4-3 = 1ft\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |